In a common base transitor amplifier, the input and the output resistance area `500Omega` and `40kOmega` and the emitter current is `1.0mA` find the input and the output voltages. Given `alpha=0.95`.

Explanation

The input voltage is emitter current multiplied by input resistance that is,
`V_("in")=i_(E)xxR_("in")=(1.0xx10^(-3)A)xx500Omega=0.5V`
Similarly the output voltage is
`V_(out)=i_(C)xxR_(out)=alphai_(E)=0.95(1.0xx10^(-3)A)xx(40xx10^(3)Omega)=38V`.