To get an output `y=1` from the circuit shown below, the input must be

Options

A. `A=0,B=1,C=0`
B. `A=0,B=0,C=0`
C. `A=1,B=0,C=1`
D. `A=1,B=0,C=0`

Answer

C

Explanation

The Boolean expression of the given circuit is
`Y=(A+B).C`
The table truth of the given input signals as shown in the table
`{:("A B C A+B Y=(A+B).C"),("0 1 0 1 0"),("0 0 1 0 0 "),("1 0 1 1 1 "),("1 0 0 1 0"):}`
From the table truth we conclude that output
`Y=1`, for the input `A=1,B=0,C=1`
For the inputs `A=1,B=0,C=1`
Hence option (3) is correct