If three different liquid of different masses specific heats and temperature are mixed with each other and then what is the temperature mixture at thermal equilibrium.
`m_(1),s_(1),T_(1) rarr` specification for liquid
`m_(2),s_(2),T_(2)rarr`specification for liquid.
`m_(3),s_(3),T_(3)rarr` specification for liquid.

Explanation

Total heat lost or gain by all substance is equal to zero
`DeltaQ =0`
`m_(1)s_(1) (T-T_(1)) +m_(2)s_(2) (T -T_(2)) +m_(3)s_(3) (T-T_(3)) =0`
so `T = (m_(1)s_(1)T_(1)+m_(2)s_(2)T_(2)+m_(3)s_(3)T_(3))/(m_(1)s_(1)+m_(2)s_(2)+m_(3)s_(3))`