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What is the percentage change in length of `1m` iron rod it its temperature changes by `100^(@)C. alpha` for iron is `2 xx 10^(-5)//"^(@)C`.

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percentage change in length due to temperature change
`%l = (Deltal)/(l) xx 100 = alpha Delta theta xx 100`
`=2 xx 10^(-5) xx 100 xx 100`
`=0.2%`
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