A steel rod is clamped at its two ends and rests on a fixes horizontal base. The rod is unstrained at `20^@C`. Find the longitudinal strain developed in the rod if the temperature rises to `50^@C`. Coefficient of linear expansion of steel `=1.2 xx 10^(-5 @)C^(-1)`.

Explanation

as we known that strain
strain `("change in length")/("original length") = (Deltal)/(l_(0))`
`:.` Strain `= alpha Delta theta`
`1.2 xx 10^(-5)xx (50-20) = 3.6 xx 10^(-4)`
here strain is compressive strian because final length is smaller than initial length.