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A uniform solid brass sphere is rotating...

A uniform solid brass sphere is rotating with angular speed `omega_0` about a diameter. If its temperature is now increased by `100^@C`, what will be its new angular speed. (given`alpha_B=2.0xx10^-5per^@C`)

A

`(omega_(0))/(1-0.002)`

B

`(omega_(0))/(1+0.002)`

C

`(omega_(0))/(1+0.004)`

D

`(omega_(0))/(1-0.004)`

Text Solution

Verified by Experts

`I_(0) omega_(0) = I_(t) omegat`
`Mr_(0)^(2) omega_(0) = Mr_(0)^(2) (1+2 alpha Delta T) omega_(t)`
`omega_(t) = (omega_(0))/(1+0.004)`
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