In `Pt(C_(2)H_(4))_(2)" "(C_(2)F_(4))` molecule, in which the platinum and all six carbon atoms are almost coplanar, choose the correct statement(s).

Options

A. C-C distance is greater in `C_(2)F_(4)" than "C_(2)H_(4)`
B. `Pt-C(of C_(2)H_(4))` distance is greater than `Pt-C(ofC_(2)F_(4))`
C. If `C_(2)H_(4)` is replaced by `C_(2)(CN)_(4)` in the complex, then C-C distance is greater in `C_(2)(CN)_(4)` than `C_(2)F_(4)`. (double bond length)
D. In case of `underline(C)(CN)_(4)` in the complex, above, the underlined C-hybridisationis `underset(n to 3)lim sp^(n)`.

Answer

A, B, C, D

Explanation

.`C_(2)F_(4)` has greater acceptance of electron into `pi^(*)` than `C_(4)H_(4)`.Hence,C-C B.L. of `C_(2)H_(4)uarr`.
.Due to synergic bonding M-C bond (of `C_(4)F_(4)`) becomes stronger.
. `C_(2)(CN)_(4)` also has synergic bonding. Due to back donation from metal to `pi^(*)`orbital ,C=C approaches c-c behaviour `(sp^(3))`