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Geometrical isomerism arises in heterole...

Geometrical isomerism arises in heteroleptic complexes due to different possible geometrical arrangement of the ligands. Important examples of this behaviour are found with coordination number 4 and 6. Such isomerism is not possible for a tetrahedral geometry but it is possible for square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical isomers are mirror images that cannot be superimposed on one another. These are called enantiomers. Optical isomerism is common in octahedral complexes involving bedentate ligands.
Select the correct statement.

A

Both `[NiCl_(2)(PPh_(3))_(2)]` and its analogous Pd(II) show geometrical isomerism.

B

`[CoBrCl(en)_(2)]` will show geometrical isomerism but is chiral compound.

C

`cis-[Co(NH_(3))_(4)Br_(2)]^(+)` can exist as enantiomer

D

A complex of palladium (II) with two chloride ions and two thiocyanate ions will show linkage as well as geometrical isomerism.

Text Solution

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The correct Answer is:
D
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Geometrical isomerism arises in heteroleptic complexes due to different possible geometrical arrangement of the ligands. Important examples of this behaviour are found with coordination number 4 and 6. Such isomerism is not possible for a tetrahedral geometry but it is possible for square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical isomers are mirror images that cannot be superimposed on one another. These are called enantiomers. Optical isomerism is common in octahedral complexes involving bedentate ligands. Which one of the following statements is false ?

Geometrical isomerism arises in heteroleptic complexes due to different possible geometrical arrangement of the ligands. Important examples of this behaviour are found with coordination number 4 and 6. Such isomerism is not possible for a tetrahedral geometry but it is possible for square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical isomers are mirror images that cannot be superimposed on one another. These are called enantiomers. Optical isomerism is common in octahedral complexes involving bedentate ligands. The total number of isomers possible for the complex [Co(en)_(2)Cl_(2)]^(+) is :

Geometrical isomerism arises in heteroleptic complexes due to different possible geometrical arrangement of the ligands. Important examples of this behaviour are found with coordination number 4 and 6. Such isomerism is not possible for a tetrahedral geometry but it is possible for square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical isomers are mirror images that cannot be superimposed on one another. These are called enantiomers. Optical isomerism is common in octahedral complexes involving bedentate ligands. Which of the following complexes will show geometrical isomerism ?

Geometrical isomerism arises in heteroleptic complexes due to different possible geometrical arrangement of the ligands. Important examples of this behaviour are found with coordination number 4 and 6. Such isomerism is not possible for a tetrahedral geometry but it is possible for square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical isomers are mirror images that cannot be superimposed on one another. These are called enantiomers. Optical isomerism is common in octahedral complexes involving bedentate ligands. For which of the following complexes, are optical isomers possible ? (P) [Cr("ox")_(3)]^(3-)" "(Q) [Cr(NH_(3))_(4)("ox")]^(+) (R ) [Co("ox")_(2)(NH_(3))_(2)]^(-) Select the correct answer using the codes given below :

Optical isomerism is shown by octahedral complexes