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Number of stereoisomers of the given com...

Number of stereoisomers of the given compound is
`CH_(3)-CH=CH-underset(OH)underset(|)(CH)-CH_(3)`

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Total number of stereoisomers of the compound CH_(3)-CH=CH- underset(OH) underset(|)(CH)-CH=CH-CH_(3) is :

Total number of stereoisomers of the compound CH_(3)-CH=CH-underset(OH)overset(|)(CH)-CH=CH-CH_(3) is

Total number of stereoisomer of compound CH_(3)-CH=CH-underset(CH_(3))underset(|)CH-CH=CH-CH_(3)

Total number of stereoisomers of given compound will be CH_(3)-underset(Cl)underset(|)(CH)-underset(Cl)underset(|)(CH)-underset(Cl)underset(|)(CH)-CH_(3)

Total number of stereoisomer of given compound will be : CH_(3)-underset(Cl) underset(|)(CH)-underset(Br) underset(|)(CH)-underset(OH) underset(|)(CH)-CH_(3)

The number of meso form of the given compound is : CH_(3)-underset(OH) underset(|)(CH)-underset(OH) underset(|)(CH)-underset(OH) underset(|)(CH)-CH_(3)

The number of meso from of the given compound is : CH_(3)-underset(OH)underset(|)(CH)-underset(OH)underset(|)(CH)-underset(OH)underset(|)(CH)-CH_(3)

Total number of stereoisomers of compound is: CH_(3)-underset(OH)underset(|)CH-underset(Br)underset(|)CH-CH_(3)

The IUPAC name of the compound is CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH(OH)-CH_(2)