`x/2 + y/3 + z/6 = 12` , `-x/6 + y/2 +z/3 = 8` , `x/2 +z/3 =10` Find the value of x,y,z.

Solve x + 2y + z = 8 , 2x - y + z = 3 , x - 2y + 3z = 6 by matrix method

x+y+z=6 x + 2z =7, 3x + y + z = 12

If x^(2)+y^(2)+z^(2)=2(x-y-z)-3 Find the value of 2x-3y+4z

If x + y + z = 6 and x^2 + y^2 + z^2= 20 then the value of x^3 + y^3 + z^3 - 3xyz is

solve x + 2y + 3z = 8 2x + y + z = 8 x + y + 2z = 6 .

If x+y+z=8\ \ a n d\ \ \ x y+y z+z x=20 , find the value of x^3+y^3+z^3-3x y z

If x^(3) + y^(3) + z^(3) = 3xyz and x + y + z = 0 , find the value of : ((x+y)^(2))/(xy) + ((y+z)^(2))/(yz) + ((z+x)^(2))/(zx)

If x+y+z=12 and x^2+y^2+z^2=96 and 1/x+1/y+1/z=36 , then find the value of x^3+y^3+z^3

Add: 5x - 8y + 2z, 3z - 4y - 2x, 6y - z - x and 3x - 2z - 3y