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If the multiplicative inverse of a compl...

If the multiplicative inverse of a complex number is ` (sqrt2 +5i)/17` ,then the complex number is

A

`(sqrt2 -5i)/17`

B

`(sqrt2 +5i)/29`

C

`17/27 (sqrt2 -5i)`

D

`17/27 (sqrt2 +5i)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the complex number given its multiplicative inverse, we can follow these steps: ### Step 1: Define the complex number Let the complex number be \( z \). ### Step 2: Write the multiplicative inverse The multiplicative inverse of \( z \) is given as: \[ z^{-1} = \frac{\sqrt{2} + 5i}{17} \] ### Step 3: Express \( z \) in terms of its inverse From the definition of multiplicative inverse, we know: \[ z = \frac{1}{z^{-1}} \] Substituting the value of \( z^{-1} \): \[ z = \frac{1}{\frac{\sqrt{2} + 5i}{17}} = \frac{17}{\sqrt{2} + 5i} \] ### Step 4: Rationalize the denominator To simplify \( z \), we multiply the numerator and the denominator by the conjugate of the denominator: \[ z = \frac{17(\sqrt{2} - 5i)}{(\sqrt{2} + 5i)(\sqrt{2} - 5i)} \] ### Step 5: Calculate the denominator Now, calculate the denominator using the formula \( (a + bi)(a - bi) = a^2 + b^2 \): \[ (\sqrt{2})^2 + (5)^2 = 2 + 25 = 27 \] ### Step 6: Substitute back into the equation Now substitute back into the equation for \( z \): \[ z = \frac{17(\sqrt{2} - 5i)}{27} \] ### Step 7: Separate real and imaginary parts Thus, we can express \( z \) as: \[ z = \frac{17\sqrt{2}}{27} - \frac{85i}{27} \] ### Final Result The complex number \( z \) is: \[ z = \frac{17\sqrt{2}}{27} - \frac{85i}{27} \] ---
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