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If z=x+i y , then he equation |(2z-i)//(...

If `z=x+i y` , then he equation `|(2z-i)//(z+1)|=m` represents a circle, then `m` can be `1//2` b. `1` c. `2` d. `3

A

` m = 1/2 `

B

m=1

C

m =2

D

m= 3

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A, B, D
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