Expand: `(x- 1/y)^11, y!=0`

Explanation

By using binomial theorem, we get
`(x-(1)/(y))^(11)=.^(11)C_(0)x^(11)((1)/(y))^(0)-.^(11)C_(1)x^(10)((1)/(y))+.^(11)C_(2)x^(9)((1)/(y))^(2)-.^(11)C_(3)x^(8)((1)/(y))^(3)+.^(11)C_(4)x^(7)((1)/(y))^(4)-` . . .
. . . . `.^(11)C_(5)x^(6)((1)/(y))^(5)+.^(11)C_(6)x^(5)((1)/(y))^(6)-.^(11)C_(7)x^(4)((1)/(y))^(7)+.^(11)C_(8)x^(3)((1)/(y))^(8)-.^(11)C_(9)x^(2)((1)/(y))^(9)+.^(11)C_(10)x((1)/(y))^(10)-.^(11)C_(11)((1)/(y))^(11)`
`=x^(11)-11(x^(10))/(y)+55(x^(9))/(y^(2))-165(x^(8))/(y^(3))+330(x^(7))/(y^(4))-462(x^(6))/(y^(5))+462(x^(5))/(y^(6))-330(x^(4))/(y^(7))+165(x^(3))/(y^(8))-55(x^(2))/(y^(9))+(11x)/(y^(10))-(1)/(y^(11))`