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If C(r) stands for .^(n)C(r)=(n!)/(r!n-r...

If `C_(r)` stands for `.^(n)C_(r)=(n!)/(r!n-r!) and underset(r=1)overset(n)(sum)r.C_(r)^(2)=lamda` for `n ge 2`, then `lamda` is divisible by

A

`3(n-1)`

B

`n+1`

C

`n(2n-1)`

D

`n^(2)+1`

Text Solution

Verified by Experts

The correct Answer is:
C
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