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If x=(1-t^2)/(1+t^2) and y=(2t)/(1+t^2),...

If `x=(1-t^2)/(1+t^2)` and `y=(2t)/(1+t^2)`, prove that `dy/dx+x/y=0`

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Given , ` x = (1-t^(2))/(1+ t^(2)) , y = (2t)/(1+t^(2))`
` (dx)/(dt) = ((1+t^(2))(-2t)-(1-t^(2))(2t))/((1+t^(2))^(2))= (-4t)/((1+t^(2))^(2))`
` (dy)/(dt) = ((1+t^(2))(2)-(2t)(2t))/((1+t^(2))^(2))= (2-2t^(2))/((1+t^(2))^(2))`
` (dy)/(dx)= ((dy)/(dt))/((dx)/(dt)) = ((1-t^(2))/(1+t^(2))) ((1+t^(2))/(-2t))`
` = (x)(-1/y)`
`(dy)/(dx) + x/y=0`
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