Home
Class 12
MATHS
Find the domain of continuity of f(x) ...

Find the domain of continuity of f(x) = ` sin^(-1) x - [x]` , [] represents greatest integer function .

Text Solution

AI Generated Solution

The correct Answer is:
To find the domain of continuity of the function \( f(x) = \sin^{-1}(x) - [x] \), where \([x]\) represents the greatest integer function, we will analyze the continuity of each component of the function. ### Step 1: Determine the domain of \( \sin^{-1}(x) \) The function \( \sin^{-1}(x) \) is defined for \( x \) in the interval \([-1, 1]\). Therefore, the domain of \( \sin^{-1}(x) \) is: \[ D_1 = [-1, 1] \] ### Step 2: Determine the domain of the greatest integer function \([x]\) The greatest integer function \([x]\) is defined for all real numbers \( x \). Therefore, the domain of \([x]\) is: \[ D_2 = \mathbb{R} \] ### Step 3: Find the common domain The overall domain of the function \( f(x) \) will be the intersection of the domains of \( \sin^{-1}(x) \) and \([x]\): \[ D = D_1 \cap D_2 = [-1, 1] \] ### Step 4: Identify points of discontinuity The function \( f(x) \) can be expressed as the difference of two functions. The function \( \sin^{-1}(x) \) is continuous on its domain \([-1, 1]\). However, the greatest integer function \([x]\) is discontinuous at every integer point. Within the interval \([-1, 1]\), the integer points are \( -1, 0, \) and \( 1 \). We need to check the continuity of \( f(x) \) at these points: - At \( x = -1 \): - \( f(-1) = \sin^{-1}(-1) - [-1] = -\frac{\pi}{2} - (-1) = -\frac{\pi}{2} + 1 \) - At \( x = 0 \): - \( f(0) = \sin^{-1}(0) - [0] = 0 - 0 = 0 \) - At \( x = 1 \): - \( f(1) = \sin^{-1}(1) - [1] = \frac{\pi}{2} - 1 \) The function \( f(x) \) is discontinuous at \( x = -1, 0, \) and \( 1 \) because the greatest integer function \([x]\) has jump discontinuities at these points. ### Step 5: Define the domain of continuity Thus, the function \( f(x) \) is continuous on the open intervals between these discontinuities: \[ \text{Domain of continuity} = (-1, 0) \cup (0, 1) \] ### Final Answer The domain of continuity of \( f(x) = \sin^{-1}(x) - [x] \) is: \[ (-1, 0) \cup (0, 1) \]

To find the domain of continuity of the function \( f(x) = \sin^{-1}(x) - [x] \), where \([x]\) represents the greatest integer function, we will analyze the continuity of each component of the function. ### Step 1: Determine the domain of \( \sin^{-1}(x) \) The function \( \sin^{-1}(x) \) is defined for \( x \) in the interval \([-1, 1]\). Therefore, the domain of \( \sin^{-1}(x) \) is: \[ D_1 = [-1, 1] \] ...
Promotional Banner

Topper's Solved these Questions

  • CONTINUITY AND DIFFERENTIABILITY

    AAKASH INSTITUTE|Exercise Assignment ( section -A)|61 Videos
  • CONTINUITY AND DIFFERENTIABILITY

    AAKASH INSTITUTE|Exercise Section -B|35 Videos
  • CONTINUITY AND DIFFERENTIABILITY

    AAKASH INSTITUTE|Exercise section - J|6 Videos
  • CONIC SECTIONS

    AAKASH INSTITUTE|Exercise SECTION - J ( Aakash Challengers Questions )|14 Videos
  • DETERMINANTS

    AAKASH INSTITUTE|Exercise SECTION - J|12 Videos

Similar Questions

Explore conceptually related problems

Find the domain and range of f(x)="sin"^(-1)(x-[x]), where [.] represents the greatest integer function.

Let f(x) = [x] and [] represents the greatest integer function, then

Discuss the continuity of f(x)=[tan^(-1)x] represents the greatest integer function).

The domain of definition of f(x)=sin^(-1)[2-4x^(2)] is ([.] denotes the greatest integer function).

Draw the graph and find the points of discontinuity for f(x)=[x^(2)-x-1],x in[-1,2] ([.] represents the greatest integer function).

Find the domain of the function f(x)=(1)/([x]^(2)-7[x]-8) , where [.] represents the greatest integer function.

Draw the graph and discuss the continuity of f(x)=[sin x+cos x],x in[0,2 pi), where [.] represents the greatest integer function.