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Evaluate -int(2pi)^(0)|sinx|dx...

Evaluate `-int_(2pi)^(0)|sinx|dx`

Text Solution

Verified by Experts

Let `I=-int_(2pi)^(0)|sinx|dx=int_(0)^(2pi)|sinx|dx` (Prop. `P_(1)`)
`=int_(0)^(pi)sinxdx+int_(pi)^(2pi)(-sinx)dx` (Prop. `P_(2)`)
[`:'sinx` is `+ve` in `I` and `II` and `-ve` in `III` and `IV` quadrant] ltbr. `=2+2=4`
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