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int loge xdx = int 1/(logx e) dx =...

`int log_e xdx = int 1/(log_x e) dx = `

A

`loglog_(x)e+C`

B

`(1)/((log_(x)e)^(2))+C`

C

`xlog_(e)((x)/(e))+C`

D

`e^(x)+C`

Text Solution

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