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int(2x^(2)+3)/((x^(2)-1)(x^(2)+4))dx=alo...

`int(2x^(2)+3)/((x^(2)-1)(x^(2)+4))dx=alog((x+1)/(x-1))+b"tan"^(-1)(x)/(2)` , then (a,b) is

A

`(1)/(2)`, `(1)/(3)`

B

`1`, `1`

C

`(1)/(2)`, `(1)/(2)`

D

`(1)/(3)`, `(1)/(3)`

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