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I(1)=int(0)^((pi)/2)(sinx-cosx)/(1+sinxc...

`I_(1)=int_(0)^((pi)/2)(sinx-cosx)/(1+sinxcosx)dx, I_(2)=int_(0)^(2pi)cos^(6)dx`,
`I_(3)=int_(-(pi)/2)^((pi)/2)sin^(3)xdx, I_(4)=int_(0)^(1) In (1/x-1)dx`. Then

A

`l_(1)=l_(2)=l_(3)=l_(4)=0`

B

`l_(1)=l_(2)=l_(3)=0` but `l_(4) ne 0`

C

`l_(1)=l_(3)=l_(4)=0` but `l_(2) ne 0`

D

`l_(1)=l_(4)=0` but `l_(3) ne 0`, and `l_(2) ne 0`

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I_(1)=int_(0)^((pi)/(2))(sin x-cos x)/(1+sin x cos x)dx,I_(2)=int_(0)^(2 pi)cos^(6)xdx,I_(3)=int_((pi)/(2))^((pi)/(2))sin^(3)xdx,I_(4)=int_(0)^(1)1n((1)/(x)-1)dx. Then I_(1)=I_(3)=I_(4)=0,I_(1)!=0I_(1)=I_(3)=0,I_(4)!=0I_(1)=I_(2)=0,I_(4)!=0I_(1)=I_(2)=I_(3)=0,I_(4)!=0

int_(0)^(pi//2)((sinx-cosx))/((1+sinxcosx))dx=0

int_(0)^(pi//2)(sinxcosx)/((1+sin^(4)x))dx

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If I_(1)=int_(0)^(2pi)sin^(3)xdx and I_(2)=int_(0)^(1)ln((1)/(x)-1)dx , then

I_(1)=int_(0)^((pi)/2)In (sinx)dx, I_(2)=int_(-pi//4)^(pi//4)In(sinx+cosx)dx . Then

int_(0)^(pi//2)(cosx)/((1+sin^(2)x))dx=?

int_(0)^(pi//2) (cosx )/ (1+sin^(2)x)dx=

If I_(1)=int_(0)^(pi//2) cos(sin x) dx,I_(2)=int_(0)^(pi//2) sin (cos x) dx and I_(3)=int_(0)^(pi//2) cos x dx then

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