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An athlete does not come to rest immedie...

An athlete does not come to rest immedietly after crossing the winning line due to the

A

Inertia of rest

B

Inertai of motion

C

Inertia of direction

D

None of these

Text Solution

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The correct Answer is:
### Step-by-Step Solution: 1. **Understanding the Scenario**: An athlete is running a race and crosses the winning line. The question asks why the athlete does not come to an immediate stop after crossing the line. 2. **Newton's First Law of Motion**: According to Newton's first law, an object in motion will remain in motion unless acted upon by an external force. This means that once the athlete is in motion, they will continue to move forward unless something stops them. 3. **Inertia**: The concept of inertia explains that the athlete has a tendency to keep moving in the same direction at the same speed due to their mass. This is why they do not stop immediately after crossing the finish line. 4. **Momentum**: The athlete has momentum, which is the product of mass and velocity. When they cross the finish line, they still possess this momentum, and it requires a force (like friction or a deliberate action by the athlete) to bring them to a stop. 5. **Physical Factors**: The athlete may also be focused on their performance and may not immediately think to stop. Additionally, the running surface (track) may not provide enough friction to stop instantly. 6. **Conclusion**: Therefore, the athlete does not stop immediately after crossing the winning line due to inertia, momentum, and the lack of sufficient external force acting to stop them.
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Knowledge Check

  • An athlete does not come to rest immediately after crossing the winning line due to the -

    A
    Inertia of rest
    B
    Inertia of motion
    C
    Inertia of direction
    D
    None of these
  • A block of mass 1 kg moving with a speed of 4 ms^(-1) , collides with another block of mass 2 kg which is at rest. If the lighter block comes to rest after collision, then the speed of the heavier body is

    A
    `2 ms^(-1)`
    B
    `1 ms^(-1)`
    C
    `1.5 ms^(-1)`
    D
    `0.5 ms^(-1)`
  • A block of mass 1 kg moving with a speed of 4 ms^(-1) , collides with another block of mass 2 kg which is at rest. The lighter block comes to rest after collision. The loss in KE of the system is

    A
    8 J
    B
    `4 xx 10^(-7) J`
    C
    4 J
    D
    0 J
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