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Maximum value of frictional force is ca...

Maximum value of frictional force is called

A

Limiting friction

B

Static friction

C

Sliding friction

D

Rolling friction

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The correct Answer is:
A
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A block is lying static on the floor.The maximum value of static frictional force on the block is 10N .If a horizontal force of 8N is applied to the block,what will be the frictional force on the block ________ (in N) (g = 10 m/s^(2))

Statement - 1 : Maximum value of friction force between two surfaces is mu xx" normal reaction" . where mu = coefficient of friction between surfaces. Statement - 2 : Friction force between surfaces of two bodies is always less than or equal to externally applied force.

Knowledge Check

  • Frictional forces are

    A
    gravitational forces
    B
    nuclear forces
    C
    electromagnetic forces
    D
    pseudo forces

  • When we apply a horizontal force on a body kept on horizontal floor, a horizontal force starts opposing the net applied force. This force is called frictional force and is always tangential to the contact surface. Frictional force on a moving body is called kinetic friction which is directly proportional to the normal force (f_(k)=mu_(k)N) where mu_(k) is a constant depending upon the surfaces and is called the coefficient of kinetic friction. Frictional force on a static body is called static friction. Maximum value of static friction force is (f_(s) le mu_(s)N) , where mu_(s) is coefficient of static friction. Now a man wants to slide down a block of mass m which is kept on a fixed inclined plane of inclination 30^(@) as shown in figure initially, the block is not sliding. To just start sliding the man pushes the block down the inclined with a force F. Now the block starts accelerating. To move it downwards with constant speed, the man starts pulling the block with same force. Surfaces are such that ratio of maximum static friction to kinetic friction is 2. Now, answer the following questions. What is the value of mu_(s) ?

    A
    `(4)/(3sqrt(3))`
    B
    `(2)/(3sqrt(3))`
    C
    `(3)/(3sqrt(3))`
    D
    `(1)/(2sqrt(3))`

  • When we apply a horizontal force on a body kept on horizontal floor, a horizontal force starts opposing the net applied force. This force is called frictional force and is always tangential to the contact surface. Frictional force on a moving body is called kinetic friction which is directly proportional to the normal force (f_(k)=mu_(k)N) where mu_(k) is a constant depending upon the surfaces and is called the coefficient of kinetic friction. Frictional force on a static body is called static friction. Maximum value of static friction force is (f_(s) le mu_(s)N) , where mu_(s) is coefficient of static friction. Now a man wants to slide down a block of mass m which is kept on a fixed inclined plane of inclination 30^(@) as shown in figure initially, the block is not sliding. To just start sliding the man pushes the block down the inclined with a force F. Now the block starts accelerating. To move it downwards with constant speed, the man starts pulling the block with same force. Surfaces are such that ratio of maximum static friction to kinetic friction is 2. Now, answer the following questions. What is the value of F?

    A
    `(mg)/(4)`
    B
    `(mg)/(6)`
    C
    `(mg sqrt(3))/(4)`
    D
    `(mg)/(2sqrt(3))`

    • Similar Questions

    Explore conceptually related problems

    When we apply a horizontal force on a body kept on horizontal floor, a horizontal force starts opposing the net applied force. This force is called frictional force and is always tangential to the contact surface. Frictional force on a moving body is called kinetic friction which is directly proportional to the normal force (f_(k)=mu_(k)N) where mu_(k) is a constant depending upon the surfaces and is called the coefficient of kinetic friction. Frictional force on a static body is called static friction. Maximum value of static friction force is (f_(s) le mu_(s)N) , where mu_(s) is coefficient of static friction. Now a man wants to slide down a block of mass m which is kept on a fixed inclined plane of inclination 30^(@) as shown in figure initially, the block is not sliding. To just start sliding the man pushes the block down the inclined with a force F. Now the block starts accelerating. To move it downwards with constant speed, the man starts pulling the block with same force. Surfaces are such that ratio of maximum static friction to kinetic friction is 2. Now, answer the following questions. If man continues pushing the block by force F, its acceleration would be

    Frictional force causes

    Frictional force causes

    The arrangement shown below shows a block of mass M and m, with a spring of force constant k attached to the spring fixed to the wall . What will be the maximum value of frictional force between them if mu is the coefficient of friction and the blocks move together in S.H.M with amplitude A ?

    Maximum value of static friction is .

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