Home
Class 12
PHYSICS
A car of maas M is moving on a horizonta...

A car of maas M is moving on a horizontal circular path of radius r. At an instant its speed is v and is increasing at a rate a.

A

The acceleration of the car is towards the centre of the path

B

The magnitude of the frictional force on the car is greater then `(mv^(2))/r`

C

The friction coefficient between the ground and the car is `mu = tan^(-1) (v^(2))/(rg)`

D

The friction coefficient between the ground and the car is ` mu = tan^(-1) (v^(2))/(rg)`

Text Solution

Verified by Experts

The correct Answer is:
B, C
Promotional Banner

Topper's Solved these Questions

  • LAWS OF MOTION

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION -D) Linked Comprehension Type Question (Comprehension -I)|1 Videos

  • LAWS OF MOTION

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION -D) Linked Comprehension Type Question (Comprehension -II) (Choose the correct answer :)|1 Videos

  • LAWS OF MOTION

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION -B) objective type questions (one option is correct)|33 Videos

  • KINETIC THEORY

    AAKASH INSTITUTE|Exercise EXERCISE (ASSIGNMENT) SECTION - D Assertion - Reason Type Questions|10 Videos

  • MAGNETISM AND MATTER

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION D)|26 Videos

Similar Questions

Explore conceptually related problems

A car of mass m moves in a horizontal circular path of radius r meter. At an instant its speed is Vm//s and is increasing at a rate of a m//sec^(2) . Then the acceleration of the car is:

A car of mass m moves in a horizontal circular path of radius r metre. At an instant its speed is V m//s and is increasing at a rate of a m//sec^(2) .then the acceleration of the car is

A car is moving on a circular road of radius 100m . At some instant its speed is 20m//s and is increasing at the rate of 3m//s^(2) . The magnitude of its acceleration is

A particle is moving on a circular path of 10 m radius. At any instant of time, its speed is 5ms^(-1) and the speed is increasing at a rate of 2ms^(-2) . At this instant, the magnitude of the net acceleration will be

A particle of mass 'm' is moving along a circle of radius 'r'. At some instant, its speed is 'v' and it is gaining speed at a uniform rate'a', then, at the given instant, acceleration of the mparticle is :

A pariticle is moving in a circle of radius 12m . At an instant its speed is 6m//s and the speed is increasing at the rate 4m//s^(2) . Find the acceleration of the particle.

A car is moving with speed 30m/s on a circular path of radius 500m at a given instant.Its speed is increasing at rate of 2.4m/s^(2) .Angle between acceleration and velocity at the given instant is

A car starts moving from rest on a horizontal circular road of radius of curvature R at . The speed of the car is increasing at a constant rate a. The coefficient of friction between the road and the tyres of the car is The car starts slipping at time t = t_(0) . Then t_(0) is equal to:

A car is moving with speed of 2ms^(-1) on a circular path of radius 1 m and its speed is increasing at the rate of 3ms(-1) The net acceleration of the car at this moment in m//s^2 is