If the mass of each molecules of a gas is doubled and speed is halved, find the ratio of initial and final pressure.

Explanation

`P=(1)/(3)(M)/(V)overline(V^(2))`
`P_(1)=(1)/(3)(M_(1))/(V)overline(v_(1)^(2))`
`P_(2)=(1)/(3)(M_(2))/(V)overline(v_(2)^(2))`
`(P_(1))/(P_(2))=(M_(1))/(M_(2))xx(overline(v_(1)^(2)))/(v_(2)^(2))`
`=(M)/(2M)xx(overline(v^(2)))/((1)/(4)overline(v^(2)))`
`P_(1):P_(2)=(4)/(2)=(2)/(1)=2:1`