If 3 moles of `H_(2)` gas is mixed with 2 moles of helium gas, then calculate equivalent molar mass of the gas and adiabatic exponent of the mixture?

Explanation

Given, `mu_(1)=3,M_(01)=2gm`
`mu_(2)=2,M_(02)=4`,
`f_(1)=5,f_(2)=3`
Equivalent molar mass `=(mu_(1)M_(01)+mu_(2)M_(02))/(mu_(1)+mu_(2))`
`=(3xx2+2xx4)/(3+2)`
`=(6+8)/(5)=(14)/(5)gm`
`thereforeM_(0)=(14)/(5)=2.8gm//"mole"`
let degree of freedom of mixture is f, then
`f=(mu_(1)f_(1)+mu_(2)f_(2))/(mu_(1)+mu_(2))=(3xx5+2xx3)/(3+2)=(15+6)/(5)=(21)/(5)`
thus `gamma=1+(2)/(f)=1+(2xx5)/(21)=(32)/(21)=1.476`