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Given, Avogadro's number N = 6.02 xx 10^...

Given, Avogadro's number `N = 6.02 xx 10^23` and Boltzmann's constant `k = 1.38 xx 10^-23 J//K`.
(a) Calculate the average kinetic energy of translation of the molecules of an ideal gas at `0^@ C and at 100^@ C`.
(b) Also calculate the corresponding energies per mole of the gas.

Text Solution

Verified by Experts

(a) `7.72xx10^(-27)` J/molecule
(b) 4647 Jmol.
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Knowledge Check

  • The average kinetic energy of one molecule of an ideal gas at 27^@C and 1 atm pressure is [Avogadro number N_A=6.023xx10^(23) ]

    A
    `900calK^(-1) mol^(-1)`
    B
    `6.21xx10^(-21)JK^(-1) "molecule" ^(-1)`
    C
    `336.7JK^(-1)mol^(-1)`
    D
    `3741.3 J K^(-1) mol^(-1)`

  • The average kinetic energy of the molecules of a gas at 27^(@) is 9xx10^(-20)J . What is its average K.E. at 227^(@)C ?

    A
    `5xx10^(-20)J`
    B
    `10xx10^(-20)J`
    C
    `15xx10^(-20)J`
    D
    `20xx10^(-20)J`

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    Calculate the average kinetic energy of hydrogen molecule at 0^(@)C . Given k_(B)=1.38xx10^(-23)JK^(-1) .

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