An electron falls through a small distance in a uniform electric field of magnitude `2xx10^(4)NC^(-1)`. The direction of the field reversed keeping the magnitude unchanged and a proton falls through the same distance. The time of fall will be

Explanation

`t_(e ) = sqrt((2S)/(a_(e)))= sqrt((2sm_(e))/(eE))`
`= sqrt((2 xx 1.5 xx 10^(-2) xx 9.1 xx 10^(-31))/( 1.6 xx 10^(-19) xx 2 xx 10^(4)))`
` = 2.9 xx 10^(-9) s`
`t_(p) = sqrt((2s)/(a_(p))) = sqrt((2sm_(P))/(eE))`
`= sqrt((2 xx 1.5 xx 1^(-2) xx 1.67 xx 10^(-27))/( 1.6 xx 10^(-19) xx 2xx 10^(4)))`
`= 1.3 xx 10^(7)s`