Home
Class 12
PHYSICS
The unit of permittivity of free space e...

The unit of permittivity of free space `epsilon_(0)` is:

A

coulomb `//` newton-metre

B

coulom`b^(2) //`newton -metre`^(2)`

C

newton-metr`e^(2) //`coulom`b^(2)`

D

coulom`b^(2) //`(newton-metre`)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
2
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTRIC CHARGES AND FIELDS

    AAKASH INSTITUTE|Exercise SECTION-B(OBJECTIVE TYPE QUESTION( ONLY ONE ANSWER)|11 Videos
  • ELECTRIC CHARGES AND FIELDS

    AAKASH INSTITUTE|Exercise SECTION-C ( OBJECECTIVE TYPE QUESTIONS)|1 Videos
  • ELECTRIC CHARGES AND FIELDS

    AAKASH INSTITUTE|Exercise TRY YOURSELF|33 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION-D)|10 Videos
  • ELECTROMAGNETIC INDUCTION

    AAKASH INSTITUTE|Exercise ASSIGNMENT(SECTION -D) Assertion-Reason type Question)|15 Videos

Similar Questions

Explore conceptually related problems

The units of absolute permittivity of free space epsilon in S.I..are

The units of absolute permittivity of free space (epsilon) in S.I.are (a) newton / coulomb (b) newton metre (c) volt / metre (d) farad / metre.

Knowledge Check

  • If the electric flux entering and leaving a closed surface are 6 xx 10^6 and 9 xx 10^6 SI units respectively, then the net charge inside the surface of permittivity of free space epsilon_0 is

    A
    `epsilon_0xx10^6`
    B
    `-epsilon_0xx10^6`
    C
    `-2epsilon_0 xx10^6`
    D
    `3epsilon_0xx10^6`
  • SI unit of permittivity is

    A
    `C^(2)m^(2)N^(-1)`
    B
    `C^(-1)m^(2)N^(-2)`
    C
    `C^(2)m^(2)N^(2)`
    D
    `C^(2)m^(-2)N^(-1)`
  • The value of permittivity of free Space is

    A
    `9xx10^9Nm^2//C^2`
    B
    `8.85xx10^-12Nm^2//C^2-5`
    C
    `8.85xx10^-12C^2//Nm^2`
    D
    `9xx10^9C^2//Nm^2`
  • Similar Questions

    Explore conceptually related problems

    The speed of light in vacuum, c, depends on two fundamental constants, the permeability of free space, mu_(0) and the permittivity of free space, epsilon_(0) . The speed of light is given by c=(1)/(sqrt(mu_(0)epsilon_(0))) . The units for mu_(0) are

    A system of two parallel plates, each of area A, are separated by distance d_(1) and d_(2) . The space between them is filled with dielectrices of permitivities epsilon_(1) and epsilon)_(2) . The permittivity of free space is epsilon_(0) . The equivalent capacitance of the system is

    The dimensional formula for permittivity of free space (epsilon_0) in the equation F ==1/(4piepsilon_0),(q_1q_2)/(r^2) , where symbols have usual meaning is

    SI unit of in_(0) (permittivity of free space) is:

    The value of electric permittivity of free space is