Home
Class 12
PHYSICS
A metallic sphere of radius R is cut in ...

A metallic sphere of radius R is cut in two parts along a plane whose minimum distance from the sphere's centre is `h=R/2` and the sphere is uniformly charges by a total charged by a total electric charge Q. The minimum force necessary (to be applied on each of the two parts) to hold the two parts of the sphere together is `(3kQ^(2))/(p R^(2))`. Then find the value of p ?

Text Solution

Verified by Experts

`(Q^(2))/( 32 pi epsilon_(0)R^(4))(R^(2) - h^(2))`
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC CHARGES AND FIELDS

    AAKASH INSTITUTE|Exercise SECTION-I(SUBJECTIVE TYPE QUESTIONS)|2 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION-D)|10 Videos

  • ELECTROMAGNETIC INDUCTION

    AAKASH INSTITUTE|Exercise ASSIGNMENT(SECTION -D) Assertion-Reason type Question)|15 Videos

Similar Questions

Explore conceptually related problems

Metallic sphere of radius R is charged to potential V. Then charge q is proportional to

A hallow metal sphere of radius R is uniformly charged. The electric field due to the sphere at a distance r from the centre:

A conducting sphere of radius R is charged to a potential of V volts. Then the electric field at a distance r ( gt R) from the centre of the sphere would be

Charge density of a sphere of radius R is rho = rho_0/r where r is distance from centre of sphere.Total charge of sphere will be

A non-conducting solid sphere of radius R is uniformly charged. The magnitude of the electric filed due to the sphere at a distance r from its centre

A sphere of radius 2R has a uniform charge density p. The difference in the electric potential at r = R and r = 0 from the centre is:

Consider a neutral metal sphere of radius "R" .A small charge q is kept at a minimum distance "d(>R)" from the surface of the sphere. Find potential due to the induced charges at the point "P" of the sphere that is at minimum distance from charge "q" ?