Calculate the earth's potential. Assume earth has a surface charge density of 1` "ectron/metre"^(2)`.(Given,the electronic charge = `-1.6xx10^(-19)C," earth's radius "=6.4 xx10^(6)m,e_(0) = 8.9xx10^(-12)c^(2)//Nm^(2)`)

Explanation

`V = (1)/( 4pi epsilon_(0)) . ( - e ( 4pi r^(2)))/( r ) = ( - er )/( epsilon_(0))`
`= ( - 1.6 xx 10^(-19)xx 64 xx 10^(5))/( 8.85 xx 10^(-12))`
`= - 0.116 `volt
`:. E = (V)/( r ) = ( - 0 . 116 )/( 64 xx 10^(5)) = - 1.8 xx 10^(-6) `volt `//` m