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STATEMENT-1: If potential energy of a di...

STATEMENT-1`:` If potential energy of a dipole in stable equilibrium position is zero, its potential energy is unstable equilibrium position will be 2pE, where p and E represent the dipole moment and electric field respectively
and
STATEMENT-2 `:` The potential energy of a dipole is minimum in stable equilibruim positioni and maximum in unstable equilibrium position.

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1

B

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False , Statement-2 is True

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze both statements regarding the potential energy of a dipole in electric fields. ### Step 1: Understanding Potential Energy of a Dipole The potential energy (U) of a dipole in an electric field (E) is given by the formula: \[ U = -\vec{p} \cdot \vec{E} \] where \( \vec{p} \) is the dipole moment vector. ### Step 2: Analyzing Stable Equilibrium In stable equilibrium, the dipole is aligned with the electric field. The potential energy is minimized, and the formula becomes: \[ U_{stable} = -pE \] If we assume that the potential energy in this position is zero, we can set: \[ -pE = 0 \] This implies that either \( p \) or \( E \) must be zero, which is not typical in a dipole scenario. However, if we take the reference point where the potential energy is zero, we can analyze the unstable equilibrium. ### Step 3: Analyzing Unstable Equilibrium In unstable equilibrium, the dipole is oriented opposite to the electric field. The potential energy is maximized, and the formula becomes: \[ U_{unstable} = pE \] If we consider the potential energy in stable equilibrium as zero, then the potential energy in unstable equilibrium can be expressed as: \[ U_{unstable} = 2pE \] This means that the potential energy in the unstable position is indeed twice that of the stable position. ### Step 4: Conclusion Thus, we can conclude that: - **Statement 1** is true: If the potential energy of a dipole in stable equilibrium is zero, then its potential energy in unstable equilibrium will be \( 2pE \). - **Statement 2** is also true: The potential energy of a dipole is minimum in stable equilibrium and maximum in unstable equilibrium. ### Final Answer Both statements are true. ---
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Knowledge Check

  • In a conservative field at stable equilibrium potential energy is:

    A
    maximum
    B
    minimum
    C
    constant
    D
    maximum or minimum
  • Assertion :Mean positon of SHM is the stable equlibrium position. Reason: In stable equilibrium , position potential energy is minimum.

    A
    If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
    B
    If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
    C
    If Assertion is true but Reason is false.
    D
    If Assertion is false but Reason is true.
  • Potential energy of a particle at position x is given by U=x^(2)-5x . Which of the following is equilibrium position of the particle?

    A
    `x=0`
    B
    `x=5`
    C
    `x=2.5`
    D
    `x=7.5`
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