STATEMENT-1 `:` If distance between plates of charged and isolated parallel plate capacitor increases then force between plates decreases.
and
STATEMENT-2 `:` Force between two point charges is inversely proportional to the square of distance of separation.

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False
D. Statement-1 is False , Statement-2 is True

Answer

To analyze the given statements, we will break down the concepts involved and derive the conclusions step by step.

### Step-by-Step Solution:

**Step 1: Understand Statement 1**
- Statement 1 claims that if the distance between the plates of a charged and isolated parallel plate capacitor increases, then the force between the plates decreases.
- For a parallel plate capacitor, the electric field (E) between the plates is given by:
\[ E = \frac{Q}{A \epsilon_0} \]
where \(Q\) is the charge on the plates, \(A\) is the area of the plates, and \(\epsilon_0\) is the permittivity of free space.

**Hint for Step 1:** Recall the formula for electric field in a parallel plate capacitor and its dependence on charge and area.

**Step 2: Calculate the Force Between the Plates**
- The force (F) on one plate due to the electric field created by the other plate is given by:
\[ F = Q \cdot E \]
- Substituting the expression for the electric field, we have:
\[ F = Q \cdot \frac{Q}{A \epsilon_0} = \frac{Q^2}{A \epsilon_0} \]
- Notice that this expression does not include the distance (d) between the plates.

**Hint for Step 2:** Understand that the force derived does not depend on the distance between the plates for an isolated capacitor.

**Step 3: Analyze the Effect of Increasing Distance**
- Since the force expression does not contain the distance variable, it indicates that the force remains constant regardless of the distance between the plates for an isolated capacitor.
- Therefore, if the distance between the plates increases, the force does not decrease; it remains the same.

**Hint for Step 3:** Consider what happens to the force when the distance changes in an isolated system.

**Step 4: Understand Statement 2**
- Statement 2 states that the force between two point charges is inversely proportional to the square of the distance of separation.
- According to Coulomb's Law, the force (F) between two point charges \(Q_1\) and \(Q_2\) separated by a distance \(r\) is given by:
\[ F = k \frac{Q_1 Q_2}{r^2} \]
where \(k\) is Coulomb's constant.
- This clearly shows that as the distance \(r\) increases, the force \(F\) decreases, confirming that this statement is correct.

**Hint for Step 4:** Recall Coulomb's Law and its implications regarding the relationship between force and distance for point charges.

**Step 5: Conclusion**
- Based on the analysis:
- Statement 1 is **incorrect** because the force between the plates of an isolated capacitor does not decrease with an increase in distance.
- Statement 2 is **correct** as it accurately describes the relationship between force and distance for point charges.

### Final Answer:
- Statement 1 is incorrect.
- Statement 2 is correct.
- Therefore, the correct option is that Statement 1 is false and Statement 2 is true.