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Resistance of a conductor of length l an...

Resistance of a conductor of length l and area of cross-section A is R. If its length is doubled and area of cross-section is halved, then find its new resistance.

Text Solution

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initial length =l, Area = A
So, initial resistance `R= rho (l)/( A)`
Final length l' = 2t `, Area `A' = (A)/(2)`
New resistance `R'= rho(l')/(A') = rho ( 2t)/(((A)/(2)))= 4 rho (l)/(A) = 4R`
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Knowledge Check

  • Resistivity of a conductor of length l and cross - section A is rho . If its length is doubled and area of cross-section is halved, then its new resistivity will be .

    A
    `(rho)/(2)`
    B
    `4 rho`
    C
    `(rho)/(4)`
    D
    `rho`

  • When the length and area of cross-section both are doubled, then its resistance

    A
    will become half
    B
    will be doubled
    C
    will remain the same
    D
    will become four time

  • When the length and area of cross-section both are doubled, then its resistance

    A
    Will become half
    B
    Will be doubled
    C
    Will remain the same
    D
    Will become four times

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