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In a potentiometer arrangement a cell of...

In a potentiometer arrangement a cell of emf 1.5 V gives a balance point at 30 cm length of wire. Now, when the cell is replaced by another celle , the balance point shifts to 50 cm. What is the emf of second cell ?

Text Solution

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`epsilon_(1) = 1.5 V, l_(1) = 30 cm `
`epsilon_(2) = ? , l_(2) = 50 cm `
Using the formula for comparison of emf of cells by potentiometer , we have `(epsilon_(2))/(epsilon_(1))= ( l_(2))/(l_(1))`
`implies epsilon_(2) = ( l_(2))/( l_(1)) xx epsilon_(1) = ( 50)/( 30 ) xx 1.5 V = 2.5 V `
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