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In the given potentiometer circuit , int...

In the given potentiometer circuit , internal resistance r of the cell of emf E is to be determined. When key K is open , balance length `AN_1` is 62cm. When K is closed , balance length `AN_2` is 58cm. The value of internal resistance r is nearly

Text Solution

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If `l_(1) = 60 ` ( when K is off )
`l_(2) = 50 cm ` ( When K is on ) , then
`r= ((l_(1))/( l_(2))-1) R = (( 60)/(50)-1) 10 Omega `
`= (1)/(5) xx 10 Omega = 2Omega `
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