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The scale of galvanometer is divided int...

The scale of galvanometer is divided into `150` equal divisions. The galvanometer has a current sensitivity of `10"divisions"//mA` and the voltage sensitivity of `2"divisions"//mV`. How the galvanometer be designed to read (i) 6A per division and (ii) 1 V per division?

Text Solution

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(i) Galvanometer resistance `G = ("Full scale voltage")/("Full scale current")`
(ii) Fule scale voltage `=("No of division")/("voltage sensitivity")= (150)/(2)= 75V `
(ii) Full scale current `=("No. of divisions")/("current sensitivity ")= (15)/(10) =15mA `
(iv) `:. G= ( 75)/(15) = 5Omega `
(v) `S = (i_(g)G)/(i-i_(g))= ( 15 xx 10^(-3)xx5)/( 150 xx 6- 15 xx 10^(-3))= 8.3 xx 10^(-5) Omega`
(vi) `R= (V)/(i_(g))-G= ( 150)/(15xx10^(-3))-5 = 9995Omega`
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