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Two cells of emf E(1) and E(2) are to ...

Two cells of emf `E_(1) ` and `E_(2)` are to be compared in a potentiometer `(E_(1) gt E_(2))` . When the cells are used in series correctly , the balancing length obtained is 400 cm. When they are used in series but `E_(2)` is connected with reverse polarities, the balancing obtaiend is 200cm. Ratio of emf of cells is

A

`3:2`

B

`3:1`

C

`4:1`

D

`4:3`

Text Solution

Verified by Experts

The correct Answer is:
2
Answer (2)
`E prop l `
`implies ( E_(1)+E_(2))/(E_(1)-E_(2))= (l_(1))/(l_(2))`
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