A wire of length l and area A is connect...

A wire of length l and area A is connected to an ideal battery . The drift speed of electrons is v. If the wire is twisted to half its length, what will be the new drift speed ?

`(v )/(2)`

`(v)/(4)`

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

CURRENT ELECTRICITY
AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION-C(OBJECTIVE TYPE QUESTION ))|3 Videos
CURRENT ELECTRICITY
AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION-E (ASSERTION-REASON TYPE QUESTION)|13 Videos
CURRENT ELECTRICITY
AAKASH INSTITUTE|Exercise ASSIGNMENT(SECTION-A(OBJECTIVE TYPE QUESTIONS))|59 Videos
COMMUNICATION SYSTEMS
AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION D (Assertion-Reason)|10 Videos
DUAL NATURE OF RADIATION AND MATTER
AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION-D)|10 Videos

Similar Questions

Explore conceptually related problems

A metal wire of length l is connected to an ideal battery of emf V and it is found that drift velocity acquired by the electrons is v_(d) . If the same wire is stretched to double its length then what will be the drift velocity of electrons?

If a wire is extended to a new length , the L, the work done is

A wire of resistivity is stretched to double its length. What will be its new resistivity?

A cylindrical wire of length L and radius r has a resistance R. The resistance of another wire of the same material but half its length and half its radius will be:

If a wire of resistance R is melted and recasted to half of its length, then the new resistance of the wire will be

A long constan wire is connected across the terminals of an ideal battery. If the wire is cut in to two equal pieces and one of them is now connected to the same battery, what will be the mobility of free electrons not in the wire compared to that in the first case?

The resistance of wire of length l and area of cross-section a is x ohm. If the wire is stretched to double its length, its resistance would become:

If a wire of resistance R is melted and recasted in to half of its length, then the new resistance of the wire will be

A potentiometer wire of length 10 m is connected in series with a battery the emf of a cell balances against 250 cm length of wire if length of potentiometer wire is increased by 1 m then new balancing length of wire will be

AAKASH INSTITUTE-CURRENT ELECTRICITY-ASSIGNMENT SECTION-B(OBJECTIVE TYPE QUESTION ))

The equivalent resistance between A and B in the following figure is ...
Text Solution
|
Two electric bulbs A and B rated 200V - 100W and 200 V - 60 W are conn...
Text Solution
|
A current i passes through a wire of length l , radius of cross-sectio...
Text Solution
|
The power consumption by the circuit shown in figure at steady state i...
Text Solution
|
The current I through a conductor varies with time t as shown in figur...
Text Solution
|
The current drawn by the battery in the situation shown in figure is
Text Solution
|
In the situation shown, the current in arm PQ will be
Text Solution
|
Seven identical cells each of e.m.f. E and internal resistance r are c...
Text Solution
|
In the situation shown, resistance R(1),R(2) and R(3) are in the ratio...
Text Solution
|
In the situation shown in figure , an ideal ammeter is connected acros...
Text Solution
|
Two cells when connected in series are balanced on 6 m on a potentiome...
Text Solution
|
The resistance between the terminal point P and Q of the given infini...
Text Solution
|
Half part of a wire of resistance R is stretched to make it 1% longer ...
Text Solution
|
The effective resistance between A and B in the network shown is
Text Solution
|
In the circuit shown, the potential differences, V(1) ( between A and ...
Text Solution
|
A wire of length l and area A is connected to an ideal battery . The d...
Text Solution
|
A resistor R(1) dissipates the power P when connected to a certain gen...
Text Solution
|
In the circuit shown, the current I will be zero when R is
Text Solution
|
In an experiment, a graph was plotted of the potential difference V be...
Text Solution
|
The current flowing through the cell in the circuit shown is
Text Solution
|