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Consider a wire of length l , area of cross-section A and resistivity `rho` and resistance `(1)/(5) Omega `. Its length is increased by applying a force on it and its length increases by four times of its original length. Find the new resistance in ohms of the wire.

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Consider a wire of length l, area of cross section A, and resistivity rho with resistance 10 Omega . Its length is increased by applying a force, and it becomes four times of its original value. Find the changed resistance of the wire.

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Knowledge Check

  • If a wire is stretched to four times its length, then the specific resistance of the wire will

    A
    become 4 times
    B
    become 1/4 times
    C
    become 16 times
    D
    remain the same

  • A wire of resistance x ohm is draw out, so that its length in increased to twice its original length, and its new resistance becomes 20 Omega then x will be .

    A
    `5 Omega`
    B
    `10 Omega`
    C
    `15 Omega`
    D
    `20 Omega`

  • A wire of resistance 4 Omega is stretched to four times of its original length resistance of wire now becomes

    A
    `4Omega`
    B
    `8Omega`
    C
    `64Omega`
    D
    `16Omega`

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    A resistance 10 Omega is stretched to twice its original length . The resistance of half of the stretched wire is

    A wire of resistance 5Omega is uniformly stretched until its new length becomes 4 times the original length. Find its new resistance.

    A wire of resistance 48 Omega is uniformly stretched until its new length becomes 4 times the original length. Find its new resistance.

    A copper wire of resistance R_(0) is strerched till its length is increased to n times of its original length. What will be its new resistance?

    A resistance R is stretched to four times its length. Its new resistance will be

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