[" 9.The area bounded by the curves "y=sqrt(x),2y-x+3],[=0,x" -axis and lying in first quadrant is "]

The area bounded by the curves y=sqrt(x),2y-x+3=0, X-axis and lying in the first quadrant is

The area bounded by the curves y=sqrt(x),2y-x+3=0 , x-axis and lying in the first quadrant is

The area (in square units) bounded by the curves y=sqrt(x),2y-x+3=0 , x -axis and lying in the first quadrant is -

The area (in square units) bounded by the curves y=sqrt(x),2y-x+3=0, x-axis, and lying in the first quadrant is

The area (in square units) bounded by the curves y=sqrt(x),2y-x+3=0, x-axis, and lying in the first quadrant is

The area (in square units) bounded by the curves y=sqrt(x),2y-x+3=0, x-axis, and lying in the first quadrant is

The area (in square units) bounded by the curves : y=sqrtx, 2y-x +3 =0 x-axis , and lying in the first quadrant is :

The area (in square units) bounded by the curves y=sqrtx,2y-x+3=0 , x-axis, and lying in the fir stquadrant is :

The area (in sqaure units) bounded by the curves: y=sqrtx , 2y-x+3=0, x-axis, and lying in the first quadrant is:

Find the area bounded by the curves y=sqrt(x),2y+3=x and x -axis.