2BSE_(2m)(1),20.,(1)(sec theta-1)/(sec theta+1)=(sin^(2)theta)/((1+cos theta)^(2))

Prove: (1+sec theta)/(sec theta)=(sin^(2)theta)/(1-cos theta)

(sec^2 theta-1)/(sec^2 theta)- sin^2 theta=

Prove each of the following identities : (i) (sec theta -1)/(sec theta +1) =(sin^(2) theta)/((1+ cos theta)^(2) ) (ii) (sec theta - tan theta)/(sec theta + tan theta) = (cos^(2) theta)/((1+ sintheta)^(2))

Prove that: (sec theta-1)/(sec theta+1)=((sin theta)/(1+cos theta))^(2)

(tan theta)/(sec theta-1)-(sin theta)/(1+cos theta)=2cot theta

(tan^(2)theta)/((sec theta-1)^(2))=(1+cos theta)/(1-cos theta)

Prove that (1 + sec theta) / sec theta = sin^2 theta /(1 - cos theta)

(cos theta)/(1+sin theta)+(1+sin theta)/(cos theta)=2sec theta

(tan theta+sec theta-1)/(tan theta-sec theta+1)=(1+sin theta)/(cos theta)

(tan theta+sec theta-1)/(tan theta-sec theta+1)=(1+sin theta)/(cos theta)