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If in a DeltaABC, c = 3b and C - B = 90°...

If in a `DeltaABC`, c = 3b and C - B = 90°, then tanB=

A

`2+sqrt3`

B

`2-sqrt3`

C

3

D

`1//3`

Text Solution

Verified by Experts

The correct Answer is:
D
We have,
c=3b
`rArrsinC=2sinB` [Using sine rule]
`rArrsin(90^(@)+B)=3sinB` `[becauseC-B=90^(@)]`
`rArrcosB=3sinBrArrtanB=1/3`
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