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In a triangle ABC, a (b cos C - c cos B)...

In a triangle ABC, a (b cos C - c cos B) =

A

`a^(2)`

B

`b^(2)-c^(2)`

C

0

D

none of these

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To solve the problem \( a(b \cos C - c \cos B) \) in triangle \( ABC \), we will use the cosine rule and some algebraic manipulations. ### Step-by-Step Solution: 1. **Recall the Cosine Rule**: The cosine rule states that for any triangle with sides \( a, b, c \) opposite to angles \( A, B, C \) respectively: \[ b^2 = a^2 + c^2 - 2ac \cos B ...
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OBJECTIVE RD SHARMA-PROPERTIES OF TRIANGLES AND CIRCLES CONNECTED WITH THEM-Chapter Test
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  14. Two sides of a triangle are 2sqrt2 and 2sqrt3cm and the angle opposite...

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  15. In a triangleABC, a=13cm, b=12 and c=5cm The distance of A from BC is

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  16. In a triangleABC,B=pi/8, C=(5pi)/(8). The altitude from A to the side ...

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  17. In a DeltaABC, A=(2pi)/3, b-c=3sqrt3 cm and area(DeltaABC)=(9sqrt3)/2 ...

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  18. In DeltaABC if a=(b-c)sectheta then (2sqrt(bc))/(b-c)sin(A/2)=

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  19. In a DeltaABC, (a + b + c) (b + c - a) = lambda bc. (where symbols ha...

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  20. If in DeltaABC, a=2b and A=3B, then A is equal to

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  21. Let the angles A , B and C of triangle A B C be in AdotPdot and let b ...

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