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In a DeltaABC, sum (b + c) cos A=...

In a `DeltaABC`, `sum (b + c) cos A=`

A

a+b+c

B

a+b-c

C

a-b+c

D

none of these

Text Solution

AI Generated Solution

To solve the problem, we need to find the value of \( \sum (b + c) \cos A \) in triangle \( ABC \). ### Step-by-Step Solution: 1. **Understanding the Expression:** We start with the expression \( \sum (b + c) \cos A \). This means we need to evaluate \( (b + c) \cos A + (c + a) \cos B + (a + b) \cos C \). 2. **Expanding the Expression:** ...
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OBJECTIVE RD SHARMA-PROPERTIES OF TRIANGLES AND CIRCLES CONNECTED WITH THEM-Chapter Test
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  13. If the radius of the incircle of a triangle withits sides 5k, 6k and 5...

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  14. Two sides of a triangle are 2sqrt2 and 2sqrt3cm and the angle opposite...

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  15. In a triangleABC, a=13cm, b=12 and c=5cm The distance of A from BC is

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  16. In a triangleABC,B=pi/8, C=(5pi)/(8). The altitude from A to the side ...

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  17. In a DeltaABC, A=(2pi)/3, b-c=3sqrt3 cm and area(DeltaABC)=(9sqrt3)/2 ...

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  19. In a DeltaABC, (a + b + c) (b + c - a) = lambda bc. (where symbols ha...

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  20. If in DeltaABC, a=2b and A=3B, then A is equal to

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