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In a DeltaABC,2asin^(2)C/2+2csin^(2)A/2=...

In a `DeltaABC,2asin^(2)C/2+2csin^(2)A/2=`

A

2(s-c)

B

2(s-b)

C

2(s-a)

D

s

Text Solution

Verified by Experts

The correct Answer is:
B
Using half-angle formulae, we have
`2asin^(2)C/2+2csin^(2)A/2`
`=2axx((s-a)(s-b))/(ab)+2cxx((s-b)(s-c))/(bc)`
`=2((s-b)/b)(s-a+s-c)=2((s-b)/b){2s-(a+c)}=2(s-b)`
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OBJECTIVE RD SHARMA-PROPERTIES OF TRIANGLES AND CIRCLES CONNECTED WITH THEM-Chapter Test
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