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In a DeltaABC, (c^(2)+a^(2)-b^(2))tanB...

In a `DeltaABC,`
`(c^(2)+a^(2)-b^(2))tanB+(a^(2)+b^(2)-c^(2))tanC=`

A

`4Delta`

B

`8Delta`

C

`6Delta`

D

`12Delta`

Text Solution

Verified by Experts

We have,
`(c^(2)+a^(2)-b^(2)tanB+(a^(2)+b^(2)-c^(2))tanC`
`=2accosBxxtanB+2abcosCxxtanC`
[Using Cosine formulae]
`=2acsinB+2absinC=4Delta+4Delta=8Delta`
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