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In any DeltaABC, sin A + sin B + sin C =...

In any `DeltaABC`, sin A + sin B + sin C =

A

`(2s)/R`

B

`s/R`

C

`(3s)/R`

D

none of these

Text Solution

Verified by Experts

We have,
`R=a/(2sinA)=b/(2sinB)=c/(2sinC)`
`thereforesinA+sinB+sinC=a/(2R)=b/(2R)+c/(2R)=(a+b+c)/(2R)=s/R`
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