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ln a triangle ABC, r(1) + r =r(2) + r(3)...

ln a triangle ABC, `r_(1) + r =r_(2) + r_(3)`. lf the measure of angle A is 60°, then `s/a=`

A

`2/3`

B

2

C

`4/3`

D

`3/2`

Text Solution

Verified by Experts

We have,
`r_(1)+r=r_(2)+r_(3)`
`rArr(Delta)/(s-a)+(Delta)/s=(Delta)/(s-b)+(Delta)/(s-c)`
`rArr(2s-a)/(s(s-a))=(2s-(b+c))/((s-b)(s-c))`
`rArr((s-b)(s-c))/(s(s-a))=a/(2s-a)`
`rArrtan^(2)A/2=1/(2(s/a)-1)`
`rArr1/3=1/(2(s/a)-1)` `[because a=60^(@)]`
`rArr2(s/a)-1=3rArrs/a=2`
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