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In a DeltaABC , if tanA/2=5/6 , and tanB...

In a `DeltaABC` , if `tanA/2=5/6` , and `tanB/2=20/37`, then

A

2a=b+c

B

`agtbgtc`

C

2c=a+b

D

none of these

Text Solution

Verified by Experts

We have,
`tanA/2=5/6` and `tanB/2=20/37`
`rArrtan((A+B)/2)=(5/6+20/37)/(1-1/5xx20/37)=305/122`
`rArrcotC/2=305/122rArrtanC/2=122/305`
Clearly,
`tanA/2gttanB/2gttanC/2rArrA/2gtB/2gtC/2rArragtbgtc`
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