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If D id the mid-point of the side BC of ...

If D id the mid-point of the side BC of a triangle ABC and AD is perpendicular to AC , then

A

`b^(2)=a^(2)-c^(2)`

B

`a^(2)+b^(2)=5c^(2)`

C

`3b^(2)=a^(2)-c^(2)`

D

`3a^(2)=b^(2)-3c^(2)`

Text Solution

Verified by Experts

In `DeltaCAD`, we have
`cosC=(AC)/(AD)rArr(a^(2)+b^(2)-c^(2))/(2ab)=b/(a//2)rArra^(2)-c^(2)=3b^(2)`
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